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From: David Abrahams (dave_at_[hidden])
Date: 2005-06-09 11:49:50
It seems to me that when BOOST_TYPEOF becomes available,
boost::result_of should use it in its default implementation,
something like:
template <class F, class A>
struct result_of<F(A)>
{
typedef typename BOOST_TYPEOF(make<F>() ( make<A>() ) ) type;
};
Is that in the plan?
-- Dave Abrahams Boost Consulting www.boost-consulting.com