From: David Abrahams (dave_at_[hidden])
Date: 2003-02-10 20:00:16
"Lin Xu" <risingdragon3_at_[hidden]> writes:
>>But you can't do that ;-)
>>
>>In particular, MemberFun<A,&A::print> is incompatible with, say,
>>MemberFun<A, &A::setz>. You'd need something more like:
>>
>> MemberFun<void(A::*)(), &A::print>
>> MemberFun<void(A::*)(int), &A::setz>
>>
> Sorry, but why? The two functions have different signitures, a::print
> has a void (A::*)(), while setz has void (A::*)(int)..so they have
> different instanitations of Function:
> Function<void>::MemberFun<A,&A::print>
> Function<void,int>::MemberFun<A,&A::setz>
Oh, I didn't realize you were going to plug all the function arguments
into the Function template.
However, wouldn't writing
MemberFun<void(A::*)(int), &A::setz>
or even:
MemberFun<void(A,int), &A::setz>
instead of
Function<void, int>::MemberFun<A, &A::setz>
be a lot simpler?
> Maybe I'm missing something, or I didn't explain things well enough?
I think I just made the wrong assumptions about what your code was
trying to do.
-- Dave Abrahams Boost Consulting www.boost-consulting.com