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Subject: [geometry] Order of the result from geometry::difference algorithm
From: You Li (liyou5678_at_[hidden])
Date: 2019-02-28 00:40:45
Hi all,
I wonder if the result from geometry::difference have a specific order?
A test shows that the result comes along the linestring from start point to
end point as below[1][2].
( Two difference lines returned. The order of result is alwasy AC the
first, DB the second. )
My work depends on the order of result. I am afraid of:
1. Under other circumstances, that order varies.
2. That order of result will change in the future version of boost library.
( I use 1.58.0 for now).
But I can't find a explicit description about this in boost::geometry
documentation.
Can you help me?
[1]
[image: image.png]
[2] https://pastebin.com/xNj1W41i
#include <iostream>
#include <boost/geometry.hpp>
#include <boost/geometry/geometries/point_xy.hpp>
#include <boost/foreach.hpp>
int main()
{
    typedef boost::geometry::model::d2::point_xy<double> POINT;
    typedef boost::geometry::model::linestring<POINT> LINE;
    typedef boost::geometry::model::polygon<POINT> POLYGON;
    LINE line;
    POLYGON polygon;
    //                     Y
    //                     |
    //               -------------
    //               |     |     |
    //               |     |     |
    //   ------A>>>>>C>>>>>>>>>>>D>>>>>B-----> X
    //       start   |     |     |    end
    //       point   |     |     |   point
    //               ------|------
    //                     |
    //
    // Create line from A to B.
    boost::geometry::read_wkt("linestring(-2 0, 2 0)", line);
    boost::geometry::correct(line);
    boost::geometry::read_wkt("POLYGON((1 1, -1 1, -1 -1, 1 -1))", polygon);
    boost::geometry::correct(polygon);
    std::vector<LINE> output;
    boost::geometry::difference(line, polygon, output);
    // Result will be 2 lines.
    // A to C : LINESTRING(-2 0,-1 0)
    // D to B : LINESTRING(1 0,2 0)
    BOOST_FOREACH(LINE const& l, output)
    {
        std::cout << boost::geometry::wkt(l) << std::endl;
    }
    return 0;
}
-------------------
Thanks!
You Li