Subject: Re: [Boost-users] Scoped Pairs of functions?
From: Brian Allison (brian.w.allison_at_[hidden])
Date: 2011-08-19 07:00:09
On Thu, Aug 18, 2011 at 1:04 PM, Nat Linden <nat_at_[hidden]> wrote:
> On Wed, Aug 17, 2011 at 10:49 AM, Brian Allison
> <brian.w.allison_at_[hidden]> wrote:
>
> > I'm on a project which uses a C++ compiler, but with a lot of C-isms.
> One of those is that there are objects with pairs of functions which
> allocate/deallocate resources. I don't have time to fix all of the design
> issues with the classes that do this (yet), but within one compilation unit
> I'd like to remove the chance for leaks.
> >
> > So - if I wanted to use boost types to wrap around 2 functions f() and
> g(), where each function
> >
> > has a void or primitive return type
> > takes zero or 1 argument
> > where f() is called at some point in a scope, and then g() is called on
> exiting the scope from which f() is called and only if f() doesn't throw..
> > has its return value ignored. [Gahh....]
> >
> > Is there a boost::bind (or lambda) expression that I can wrap in a type?
> >
> > How do I generalize to include the possibility of a single argument?
>
> The following works for me with gcc 4.0.1 (yeah, I know, old compiler):
>
> #include <iostream>
> #include <boost/function.hpp>
> #include <boost/bind.hpp>
>
> void acquire_fixed()
> {
> std::cout << "Acquiring fixed resource\n";
> }
>
> void release_fixed()
> {
> std::cout << "Releasing fixed resource\n";
> }
>
> void acquire(const std::string& resource)
> {
> std::cout << "Acquiring " << resource << '\n';
> }
>
> void release(const std::string& resource)
> {
> std::cout << "Releasing " << resource << '\n';
> }
>
> class ScopedResource
> {
> public:
> typedef boost::function<void()> ResourceFunc;
> ScopedResource(const ResourceFunc& acq, const ResourceFunc& rel):
> mRelease(rel)
> {
> acq();
> }
>
> virtual ~ScopedResource()
> {
> mRelease();
> }
>
> private:
> ResourceFunc mRelease;
> };
>
> int main(int argc, char *argv[])
> {
> {
> ScopedResource fixed(acquire_fixed, release_fixed);
> std::cout << "during lifespan of 'fixed'\n";
> }
> {
> ScopedResource something(boost::bind(acquire, "something"),
> boost::bind(release, "something"));
> std::cout << "during lifespan of 'something'\n";
> }
> return 0;
> }
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>
Is there a way to generalize the return type so that ScopedResource could be
in a library and the user could use it for pairing two functions that have
int and void return types respectively?
I'm not familiar with boost::function, so I don't know if I could mod the
class and typedef to:
template *<type R1 = void, type R2 = void>*
class ScopedResource
{
public:*
typedef boost::function<R1()> ResourceFunc1; * // will this work?*
typedef boost::function<R2()> ResourceFunc2; * // will this work?*
*
and the object declarations as
{
ScopedResource fixed(acquire_fixed, release_fixed);
std::cout << "during lifespan of 'fixed'\n";
}
{
ScopedResource*<void, int>* something(*f_that_returns_int,
g_with_void_return*);
std::cout << "during lifespan of 'something'\n";
}