Subject: Re: [Boost-users] [fusion] Introspection of fused objects?
From: Rutger ter Borg (rutger_at_[hidden])
Date: 2010-02-26 03:24:50
Steven Watanabe wrote:
>
> What are you casting to a superclass?
>
The functor merge_fused above is not a proper fused function object. In this
case, I did a
template< typename Base, int N >
struct select: Base {
template< typename Seq >
void operator()( Seq& seq ) {
Base::template operator()<N>(seq);
}
}
to make N proper fused function objects. Although it is a nice trick, I
guess this was not my real question.
>
> What is the "Fused Counterpart" of Seq.
>
This is more in the direction of the real question :-) .. The question is,
I guess, if you do
g = make_fused( f )
then, are the parameter types of f still available in g somehow?
>
> Is Seq always that same type?
>
No, it is not, and I suspect it is just the sequence type passed by the
user. To make it all safe (and, if I'm going to use this approach), I guess
I neeed to pass more type information myself.
Thanks,
Cheers,
Rutger