Subject: Re: [Boost-users] Detect specialized template function?
From: Andrew Chinkoff (achinkoff_at_[hidden])
Date: 2010-01-29 07:34:30
Hi, Daniel.
Daniel wrote:
> For example, the mere existance of the specialization
> template <> void S<int>::g() { ... }
> should trigger special logic in S<int>::f().
Couldn't you explain what "trigger special logic" means?
Specializing template for concrete type we trigger special logic, don't we?
Best,
Andrew
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