Subject: Re: [Boost-users] [enable_shared_from_this] My derivation ofenable_shared_from_this wants to be templated
From: Peter Dimov (pdimov_at_[hidden])
Date: 2009-03-04 15:03:31
Rob Currey:
> template<class X>
> class Y: public enable_shared_from_this< Y<X> >
> {
> public:
>
> shared_ptr< Y<X> > f()
> {
> return shared_from_this();
In a template, you need
return this->shared_from_this();
to inform the compiler that shared_from_this will come from a base class.
> }
> };