Subject: [Boost-users] [optional] operator <<
From: Igor R (boost.lists_at_[hidden])
Date: 2009-02-19 06:45:15
Hello,
I've just noticed that the following code might be missleading:
boost::optional<int> opt;
opt = 0;
std::cout << opt;
If boost/optional/optional_io.hpp is not included, the above code outputs
"1" - because boost::optional is implicitly convertible to bool.
Maybe it's worth either including boost/optional/optional_io.hpp in
boost/optional.hpp or making some trick to generate compiler error if
operator <<() used and optional_io.hpp is not included?