From: Zeljko Vrba (zvrba_at_[hidden])
Date: 2008-08-25 12:06:04
On Mon, Aug 25, 2008 at 09:13:49AM +0200, Carsten Høyer wrote:
>
> That wouldn?t be enough would it? Then i only have the connection between the two
>
The easiest way to do it is to introduce a new node for every port, but then
you will loose the information about grouping of ports into your "original"
nodes. So you'd need an extra structure / subgraph that accomplishes the
latter. Maybe an extra property on the ports which signifies to which "node"
they belong.