From: Steven Watanabe (watanabesj_at_[hidden])
Date: 2008-07-19 00:31:46
AMDG
Robert Jones wrote:
> Gives a compiler error, which I think tells me that my lambda
> expression, _1 == 3
> does not provide the argument_type typedef. I thought lambda
> expressions were
> careful to to do this. What am I doing wrong?
Lambda can't provide argument_type typedefs in general.
Consider the following:
(_1 == 3)(1.0)
(_1 == 3)(10)
Both of these are legal. The same function object
can be called with either a double or an int. There is
no unique argument type.
In Christ,
Steven Watanabe