Re: [Boost-users] [xpressive] first try: error handling, nested refs

From: Christoph (christoph.duelli_at_[hidden])
Date: 2008-05-30 14:15:32

Dave Jenkins wrote:

> It works if you change the parenthesis:
> 
>   [ (ref(result) [ref(res_name)]) [s1] = s2 ];
It does. Thank you!

Christoph