From: Peter (p.schregle_at_[hidden])
Date: 2008-04-25 16:12:25
Ovanes,
sorry, I made an error when writing the sample. It should have been:
template <typename T>
struct point : boost::additive<point<T>, T>
{
T x_;
T y_;
explicit point(T x=0, T y=0) : x_(x), y_(y)
{ }
point & operator += (T offset)
{
x_ += offset;
y_ += offset;
return *this;
}
point & operator -= (T offset)
{
x_ -= offset;
y_ -= offset;
return *this;
}
}
This part is working as it should.
My problem comes as soon as I make member templates out of the operators, for example like so
...
template <typename U>
point & operator += (U offset)
{
x_ += offset;
y_ += offset;
return *this;
}
...
How do I write the boost::additive stuff so that it works with the operator template with all the types U that are instantiated?
Is that at all possible?
Peter
"Ovanes Markarian" <om_boost_at_[hidden]> schrieb im Newsbeitrag news:a83c1a380804250223i4e3cbcdfu17871dfb0a585600_at_mail.gmail.com...
Peter,
AFAIK operator += or operator -= signature must contain a return value. In your case it can probably be void.
template<class U>
void operator+=(U offset)
{
...
}
...
Best Regards,
Ovanes
On Fri, Apr 25, 2008 at 10:41 AM, Peter <p.schregle_at_[hidden]> wrote:
Assuming I have a class like the following:
template <typename T>
struct point : boost::additive<point<T>, T>
{
T x_;
T y_;
explicit point(T x=0, T y=0) : x_(x), y_(y)
{ }
operator += (T offset)
{
x_ += offset;
y_ += offset;
}
operator -= (T offset)
{
x_ -= offset;
y_ -= offset;
}
}
Now I want to change the addition and subtraction operators to allow for
different types using the following template
class point ...
template <typename U>
operator += (U offset)
{
x_ += offset;
y_ += offset;
}
template <typename U>
operator -= (T offset)
{
x_ -= offset;
y_ -= offset;
}
...
I cannot figure out how to write the proper syntax for the boost::additive
class, so that it generates the proper additional operators for all type
combinations. Is that possible, at all?
Thanks, Peter
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