[Boost-users] variant cast operators?

From: Daniel Oberhoff (daniel_at_[hidden])
Date: 2008-03-17 16:05:58

Hi,

I am playing with boost::variant to introduce a more elegant property 
system into my current project. I was wondering why there are no cast 
operatorst defined for the variant types, to avoid having to type get<>:

boost::variant<double,int,string> v;
string s = v;

is there a basic reason why this is not possible?

Best

Daniel