From: Matthias Troyer (troyer_at_[hidden])
Date: 2007-09-17 05:44:04
On Sep 17, 2007, at 12:45 AM, Neal Becker wrote:
> I'm stumped as to why my template typedef simulation doesn't work with
> serialization.
>
> Here's a simple example:
>
> template<typename T>
> struct A {
> };
>
> template<typename T>
> struct B {
> typedef A<T> type;
> };
>
> namespace boost { namespace serialization {
> template<class Archive, class T>
> inline void serialize (Archive &ar, typename B<T>::type & v, const
> unsigned int file_version) { <<< This won't work
> //inline void serialize (Archive &ar, A<T> & v, const unsigned int
> file_version) { <<< This is OK
> boost::serialization::split_free (ar, v, file_version);
> }
> }
> }
>
> I expected typename B<T>::type is equivalent to A<T>, but gcc-4.1.2
> doesn't
> agree. The latter compiles, but the 1st gives:
> /usr/local/src/boost.hg/boost/serialization/access.hpp:109: error:
> ‘struct
> A<int>’ has no member named ‘serialize’
This is probably because the default serialize() template which
forwards to a member function is a better match than your version.
Matthias