From: Sebastian Redl (sebastian.redl_at_[hidden])
Date: 2006-07-19 18:41:21
Sean Huang wrote:
>Is there any reason why boost::function allows such conversions?
>
>
Boost.Function tries to behave as if it were a function pointer. And
like all pointers, function pointers can be assigned an integral
constant with the value 0, resulting in a null pointer. Thus, you can
assign 0 and char() to a Boost.Function.
Sebastian Redl