From: Boris Breidenbach (Boris.Breidenbach_at_[hidden])
Date: 2006-07-10 09:29:50
On Mon, Jul 10, 2006 at 03:58:19PM +1000, bringiton bringiton wrote:
> This question is based on curiosity. How does std::vector::pop_back() call
> the destructor of the item getting removed?
>
> i understood std::vector to be a contigious array of memory, therefore an
> item's memory does not go out of scope when being popped. ie the item goes
> out of scope when the entire array goes out of scope.
just look at the include files:
bits/stl_vector.h says:
void
pop_back()
{
--this->_M_impl._M_finish;
std::_Destroy(this->_M_impl._M_finish);
}
so the destructor is called in std::_Destroy. Which can be found in
bits/stl_construct.h:
/**
* @if maint
* Destroy the object pointed to by a pointer type.
* @endif
*/
template<typename _Tp>
inline void
_Destroy(_Tp* __pointer)
{ __pointer->~_Tp(); }
It just calls the destructor.