From: John Maddock (john_at_[hidden])
Date: 2006-02-08 12:48:48
> // I would expect this to not match due to the 'w'.
> // Why does it match?
> cout << regex_match("\xF8p\x2Aqfw\x0DPFFF", reg_exp) << endl;
I believe the \x2A character is a '*' right?
If so the compiler converts \x2A to a * so the regex engine sees a ".*".
If you double up those escapes and use "\\x2A" then the regex engine will
parse the escape rather than the compiler, and so it won't be interpreted as
a quantifier anymore.
This one had me fooled for a while BTW ;-)
John.