From: David Abrahams (dave_at_[hidden])
Date: 2005-02-15 13:40:45
Ben Hutchings <ben.hutchings_at_[hidden]> writes:
> Actually it can:
>
> struct D : C { void foo(std::string); };
>
> mem_fun mf = static_cast<mem_fun>(&D::foo);
>
> Not that I'd recommend doing that, as it invites type errors.
Creating an instance by breaking the type system is cheating. Why not
reinterpret_cast<mem_fun>("foo"), for that matter?
A simpler instance of the type is:
mem_fun mf = 0;
Cheers,
-- Dave Abrahams Boost Consulting www.boost-consulting.com