From: David Abrahams (dave_at_[hidden])
Date: 2004-03-31 08:19:26
Anders Sundman <d00-asu_at_[hidden]> writes:
> (_1*_1)(_1 - _2) computes the (i1[i] - i2[i])^2 part
OK; I didn't know that's what you meant by "sum of squared
differences". I'd call that "the difference squared".
-- Dave Abrahams Boost Consulting www.boost-consulting.com