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From: Eelis van der Weegen (boost-users_at_[hidden])
Date: 2004-02-23 21:58:41
Hi,
I defined the following operator to stream optional<char>'s:
std::ostream &
operator<< (std::ostream & os, boost::optional<char> const & op)
{
if (op) os << *op; else os << '_';
return os;
}
Now, when I use:
boost::optional<char> a ('a');
std::cout << a;
'a' is printed like I expected. However, when I use:
std::ostream_iterator<boost::optional<char> > oi (std::cout);
*oi = a;
'1' is printed and my operator is apparently ignored (I expected another
'a'). Is this a gcc (3.2.3) issue or a boost issue? And in any case: is
there a workaround?
Thanks,
Eelis