Subject: Re: [boost] [typeof] deducing type at class level
From: Vicente Botet (vicente.botet_at_[hidden])
Date: 2011-06-22 13:04:02
Mathias Gaunard-2 wrote:
>
> On 22/06/2011 18:02, lcaminiti wrote:
>> Hello all,
>>
>> Is there any way to use BOOST_TYPEOF at class level? For example:
>>
>> struct vect {
>> size_t size();
>>
>> typedef BOOST_TYPEOF(size()) size_type; // can I make this work
>> somehow?
>
> typedef BOOST_TYPEOF(make<vect>().size()) size_type;
>
> with
>
> #ifndef BOOST_NO_RVALUE_REFERENCES
>
> template<class T>
> typename enable_if<
> is_reference<T>,
> T
> >::type
> make();
>
> template<class T>
> typename disable_if<
> is_reference<T>,
> T&
> >::type
> make();
>
> #else
>
> T&& make();
>
> #endif
>
>
Hi,
note that there is already declval in the standard ans in Boost.Utility taht
can be used instead of make.
20.2.4 Function template declval [declval]
1 The library provides the function template declval to simplify the
definition of expressions which occur as unevaluated operands (Clause 5).
Best,
Vicente
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