Subject: Re: [boost] [Serialization] this seems wrong
From: Steven Watanabe (watanabesj_at_[hidden])
Date: 2008-12-02 17:22:36
AMDG
Michael Marcin wrote:
> I don't know about getting rid of the unnamed namespace but
> essentially we just need a unique name per type in a translation
> unit.. so how about:
>
> #define BOOST_CLASS_EXPORT_GUID(T, K) \
> namespace \
> { \
> template< typename U > \
> class init_guid \
> { \
> static ::boost::archive::detail::guid_initializer<U> const & \
> guid_initializer_; \
> }; \
> template<> ::boost::archive::detail::guid_initializer<T> const & \
> init_guid<T>::guid_initializer_ = \
> ::boost::serialization::singleton< \
> ::boost::archive::detail::guid_initializer<T> \
> >::get_mutable_instance().export_guid(K); \
> }
With a little fiddling, I think that this might be made to work.
#define BOOST_CLASS_EXPORT_GUID(T, K) \
namespace \
{ \
template< typename U > \
class init_guid; \
template<> \
class init_guid<T> \
{ \
static ::boost::archive::detail::guid_initializer<T> const & \
guid_initializer_; \
}; \
::boost::archive::detail::guid_initializer<T> const & \
init_guid<T>::guid_initializer_ = \
::boost::serialization::singleton< \
::boost::archive::detail::guid_initializer<T> \
>::get_mutable_instance().export_guid(K); \
}
In Christ,
Steven Watanabe