From: Janek Kozicki (janek_listy_at_[hidden])
Date: 2006-10-13 07:02:08
Janek Kozicki said: (by the date of Fri, 13 Oct 2006 07:42:25 +0200)
ok. maybe you will like this:
75 failures in 13 libraries (37 are from non-broken platforms)
non-broken broken total
filesystem 0 2 2
io 1
iostreams 7 1 8
mpl 5 1 6
parameter 2 4 6
program_options 0 9 9
python 8 1 9
random 1
rational 3 2 5
serialization 4 14 18
spirit 4 3 7
test 1 1 2
utility 1
To get this:
utility 1 0 1
simply comment the line marked with [1]
The code for that:
message += (str(self.numFailures()) + ' failures in ' +
str(len(self.libraries)) + ' libraries')
if any_broken_platforms:
message += ' (' + str(self.numReportableFailures()) + ' are from non-broken platforms)'
message += '\n\n non-broken broken total\n'
# Display the number of failures per library
for k in sorted_keys( self.libraries ):
library = self.libraries[k]
num_failures = library.numFailures()
message += (' ' + library.name.ljust(22) + ' '
+ str(library.numReportableFailures()).ljust(9) )
# [1] comment this "if" line
if library.numReportableFailures() < num_failures:
message += (' ' + str(num_failures - library.numReportableFailures() ).ljust(8)
+ ' ' + str(num_failures))
message += '\n'
pass
Anyway, I'm off with that. Take it or not :)
-- Janek Kozicki |