From: Michael Goldshteyn (mgoldshteyn_at_[hidden])
Date: 2006-07-26 16:00:42
>
> The expression boost::bind( f, x, _1 ) stores copies of f, x, and _1. When
> the returned function object is called, however, _1 binds directly to the
> first input argument, without a copy. You can test this by trying it on a
> noncopyable object.
Aha, so only a copy of the boost::arg placeholder object is made where _1
appears and
this is what is copied when the binder function object is constructed.
Thanks for the clarification,
Mike