From: me22 (me22.ca_at_[hidden])
Date: 2006-07-11 10:52:39
On 7/11/06, Andy Little <andy_at_[hidden]> wrote:
> "me22" <me22.ca_at_[hidden]> wrote
> > If foo(bar,a,b) could always be written as bar.foo(a,b)
> >
> That would break some of my code FWIW
>
In what way? Would it still break with a new overload resolution rule
that a member function called as a member function is a better match
than a non-member function called as a member function?
~ Scott McMurray