From: Tobias Schwinger (tschwinger_at_[hidden])
Date: 2006-05-09 14:54:53
Tobias Schwinger wrote:
> Gerhard Wesp wrote:
>
>>On Tue, May 09, 2006 at 07:06:56PM +0200, Tobias Schwinger wrote:
>>
>>
>>> rational c = convert(a) / b
>>
>>
>>Do you already have possible overloads and return types for convert() in
>>mind?
>>
>
>
> Sure: 'convert' returns an expression, just like any other operator. That expression will be something like a reference wrapper for the argument.
>
> When the full compound expression is evaluated the convert expression protects its component expression from result type propagation.
>
> Best case, it's all it does -- the evaluation machinery can view the result of the evaluation as a value of the expected domain.
>
> For narrowing conversions and for builtins (*) the appropriate algorithm has is invoked to perform the actual conversion.
>
(*) actually not only for builtins but for types that are not "first class citizens"
of the framework...