From: Gabriel Dos Reis (gdr_at_[hidden])
Date: 2005-12-20 20:20:33
"Eric Niebler" <eric_at_[hidden]> writes:
| Gabriel Dos Reis wrote:
| > "Eric Niebler" <eric_at_[hidden]> writes:
| >
| > | Now look above it: "typedef foo const cfoo". So the type of the 3rd
| > | operand is "rvalue of foo const". The 2nd operand gets converted to
| > ^^^^^^^^^
| >
| > [there is no type "rvalue of ..." as you said earlier]
| >
|
| Thanks for the correction. So, the above would be more properly stated,
| "the 3rd operand is an rvalue of type foo const," is that right?
Yup.