From: Ariel Badichi (abadichi_at_[hidden])
Date: 2005-09-22 05:58:58
David Abrahams wrote:
>
> Maybe because it allows more than a literal zero?
>
But then again, so does assignment (and implicit conversion) to any
pointer? I'd like to have code like the following:
boost::shared_ptr<int> foo()
{
return 0;
/* instead of boost::shared_ptr<int>() */
}
boost::shared_ptr<int> p(new int(42));
p = 0; // instead of p.reset()