From: Larry Evans (cppljevans_at_[hidden])
Date: 2005-06-10 17:59:25
On 06/10/2005 05:09 PM, Jonathan Turkanis wrote:
> Larry Evans wrote:
[snip]
> The point of preprocessing certain headers is just to save the compiler from
> having to preprocess them on each compilation. The main work is done by the
> preprocessor itself.
More specifically, by the preprocess.py's:
os.system( "preprocess %s %s %s %s" % ( boost_root, mode, file,
file_path ) )
IIUC.
But then why isn't the result of this preprocessing and then clean-up
by the python code placed in:
boost/mpl/<basename>.hpp
instead of in:
boost/mpl/aux_/preprocessed/<mode>/<basename>.hpp
where <basename> is some basename of the files in boost/mpl/*.hpp and
<mode> is some directory in boost/mpl/aux_/preprocessed and also,
apparently, one possible value of mode in:
def process( file, boost_root, dst_dir, mode ):
in libs/mpl/preprocessed/preprocess.py? The way it's done now,
by using some preprocessing flags in:
boost/mpl/<basename>.hpp
to indicate whether:
boost/mpl/aux_/preprocessed/<mode>/<basename>.hpp
is to be included or not, makes it harder to understand what's
going on.