From: Andreas Huber (ahd6974-spamgroupstrap_at_[hidden])
Date: 2005-03-03 13:16:48
Andreas Huber wrote:
>> I don't think of exiting a state as
>> destroying it, just that it's no longer "active" or whatever.
>
[snip]
> Also, think of a state being
> represented by one bit. Zero means state is inactive, 1 means state
> is active. With state-local storage you can augment this one bit with
> whatever information you like.
Of course, this does not explain why the variables need to be
constructed on state entry and destructed on state-exit. So, in the
context of this discussion this is nonsense.
-- Andreas Huber When replying by private email, please remove the words spam and trap from the address shown in the header.