[boost] return type of arithmetic operators

From: Thomas Beckmann (beckmann.bremen_at_[hidden])
Date: 2004-08-07 08:25:17

Hi,

I want to use the arithmetic operators from boost/operators.hpp but found 
something strange.

If one takes for example boost::rational which uses boost::addable (and 
others), it is possible to write the following:

boost::rational<int> x, y, z;

x + y = z;

This is not possible for integral types.

Is this intended, considered minor or just overseen? Wouldn't it be better 
for the arithmetic operators to return const T instead of T?

Thank you in advance,

Thomas