From: David Abrahams (dave_at_[hidden])
Date: 2003-10-21 11:29:23
"David Bergman" <davidb_at_[hidden]> writes:
> It has to do with purity, that Haskell is a pure language in the sense of an
> expression ALWAYS evaluating to the same value, so that the same exact
> expression can be substituted for that computed value wherever, whenever.
Even I can tell that has no bearing on side-effects, though:
int z;
int f(int x) { return z = x; }
f(y) is always y for any y
still, it has side-effects.
-- Dave Abrahams Boost Consulting www.boost-consulting.com