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From: Eric Niebler (neric_at_[hidden])
Date: 2003-01-20 18:37:36
By the same reasoning, is_convertible<void(), void(*)()> should evaluate to
true, since a function type is implicitly convertible to its pointer type.
But given the current implementation (1.29.0),
is_convertible<void(),void(*)()> doesn't compile.
Opinions? Is this just too nit-picky?
Eric