From: John Maddock (John_Maddock_at_[hidden])
Date: 2000-10-14 06:58:27
Jesse,
>But what if the type is "char* const"? It won't match the specialization
>because the pointer itself is const. I think there should be a second
>specialization that looks like this:
That was how it was in one of the early (pre-release) versions, but was
changed to follow the definitions in 3.9.2 (compound types). BTW the docs
make it clear that is_pointer applies to cv-unqualified types, if you want
to ignore cv-qualifiers then use:
is_pointer<typename remove_reference<T>::type>::value
- John.