From: jsiek_at_[hidden]
Date: 2000-05-30 13:21:49
Right... my version left out "mutable".
Darin Adler writes:
> on 5/30/00 10:48 AM, jsiek_at_[hidden] at jsiek_at_[hidden] wrote:
> > template <class X, class Y>
> > struct tied
> > {
> > tied(X& x, Y& y) : m_x(x), m_y(y) {}
> >
> > template <class T1, class T2>
> > void operator=(const std::pair<T1,T2>& p)
> > { m_x = p.first; m_y = p.second; }
> > mutable X& m_x;
> > mutable Y& m_y;
> > };
>
> What does the "mutable" accomplish here? I think that you can modify objects
> through m_x and m_y regardless of whether the tied object is const or not.
> For reference members, it seems that mutable is a no-op.
>
> -- Darin
>
>
> ------------------------------------------------------------------------
> Old school buds here:
> http://click.egroups.com/1/4057/3/_/9351/_/959709343/
> ------------------------------------------------------------------------
>
>
>