Re: [boost] Cast free NULLs in algorithms

From: Stefan Seefeld (seefeld_at_[hidden])
Date: 2007-07-31 23:51:24

Eric Niebler wrote:

> I think the issue is that, although the literal "0" can be implicitly 
> converted to a pointer, when passed to std::fill(), its type is deduced 
> to be "int", at which point it can no longer be converted to a pointer.

I see ! I hadn't realized that the third parameter type was deduced from
the argument. (Instead I was fixated on the use of 'NULL' instead of '0'.)

Thanks,
                Stefan

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